Welcome to destall.com on July 10 2009.
This is an internet experiment running to monitor browsing habbits of individuals through wikipedia contents.

Quasinormal operator

From Wikipedia, the free encyclopedia

Jump to: navigation, search

In operator theory, quasinormal operators is a class of bounded operators defined by weakening the requirements of a normal operator.

Every quasinormal operator is a subnormal operator. Every quasinormal operator on a finite-dimensional Hilbert space is normal.

Contents

[edit] Definition and some properties

[edit] Definition

Let A be a bounded operator on a Hilbert space H, then A is said to be quasinormal if A commutes with A*A, i.e.

A(A^*A) = (A^*A) A.\,

[edit] Properties

A normal operator is necessarily quasinormal.

Let A = UP be the polar decomposition of A. If A is quasinormal, then UP = PU. To see this, notice that the positive factor P in the polar decomposition is of the form (A*A)½, the unique positive square root of A*A. Quasinormality means A commutes with A*A. As a consequence of the continuous functional calculus for self adjoint operators, A commutes with P = (A*A)½ also, i.e.

U P P = P U P.\,

So UP = PU on the range of P. On the other hand, if hH lies in kernel of P, clearly UP h = 0. But PU h = 0 as well. because U is a partial isometry whose initial space is closure of range P. Finally, the self-adjointness of P implies that H is the direct sum of its range and kernel. Thus the argument given proves UP = PU on all of H.

On the other hand, one can readily verify that if UP = PU, then A must be quasinormal. Thus the operator A is quasinormal if and only if UP = PU.

When H is finite dimensional, every quasinormal operator A is normal. This is because that in the finite dimensional case, the partial isometry U in the polar decomposition A = UP can be taken to be unitary. This then gives

A^*A = (UP)^* UP =  PU (PU)^* = AA^*.\,

In general, a partial isometry may not be extendable to a unitary operator and therefore a quasinormal operator need not be normal. For example, consider the unilateral shift T. T is quasinormal because T*T is the identity operator. But T is clearly not normal.

[edit] Quasinormal invariant subspaces

It is not known that, in general, whether a bounded operator A on a Hilbert space H has a nontrivial invariant subspace. However, when A is normal, an affirmative answer is given by the spectral theorem. Every normal operator A is obtained by integrating the identity function with respect to a spectral measure E = {EB} on the spectrum of A, σ(A):

A = \int_{\sigma(A)} \lambda d E (\lambda).\,

For any Borel set Bσ(A), the projection EB commutes with A and therefore the range of EB is an invariant subpsace of A.

The above can be extended directly to quasinormal operators. To say A commutes with A*A is to say that A commutes with (A*A)½. But this implies that A commutes with any projection EB in the spectral measure of (A*A)½, which proves the invariant subspace claim. In fact, one can conclude something stronger. The range of EB is actually a reducing subspace of A, i.e. its orthogonal complement is also invariant under A.

[edit] References

  • P. Halmos, A Hilbert Space Problem Book, Springer, New York 1982.
Personal tools

Visit joltnews for the latest headlines
Visit bloit.com for company information
Geed Media does computer consulting on long island.
This page viewed times. See Logs